[Practice] Process synchronization with Win32 Mutex

// to do: build the code and execute the binary twice at the same time!

int _tmain(int argc, _TCHAR* argv[])

{

    HANDLE hMutex;

    DWORD dwWaitResult;

    for( int i=0 ; i<3 ; i++ )

    {

        // if the mutex with the same name exists, it opens the mutex with MUTEX_ALL_ACCESS right.

        hMutex = CreateMutex(NULL, FALSE, _T("XXXXXXX_uid:0a0b6203-cd11-4b50-877b-3965da7275cc"));

        // waiting for other thread release the mutex

        // then this thread will get the mutex

        _tprintf( _T("Waiting for the mutex... ") );

        dwWaitResult = WaitForSingleObject(hMutex, INFINITE);

        switch(dwWaitResult)

        {

        case WAIT_OBJECT_0:

            // This thread got a mutex!

            _tprintf(_T ("thread got mutex ! \n") );

            break;

        case WAIT_TIMEOUT:

            // A time out occurs...

            _tprintf(_T ("timer expired ! \n") );

            break;

        case WAIT_ABANDONED:

            // Another thread may not release the mutex before it terminated.

            // The mutex has been abandoned.... how poor....

            _tprintf(_T ("abandoned ! \n") );

            break;

        }

        _tprintf( _T("Thread Running (%d) ! \n"), i+1 );

        for( int j=0 ; j<10 ; j++)

        {

            _puttch(_T('.'));

            Sleep(100);

        }

        _puttch(_T('\n'));

        // should release the mutex

        _tprintf( _T("One loop ended, the mutex will be released! \n\n") );

        ReleaseMutex(hMutex);

    }

    _tprintf( _T("Test has terminated.\nPress any key to continue... \n") );

    _gettch();

    return 0;

}